経済学で出る数学
ワークブックでじっくり攻める:問 5.17
【解答 5.17】
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$\left(x^{-8}\right)^{\prime}=-8x^{-9}=-\dfrac{8}{x^9}$
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$\left(\dfrac{1}{x^{3}}\right)^{\prime}=\left(x^{-3}\right)^{\prime}=-3x^{-4}=-\dfrac{3}{x^4}$
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$\left(\dfrac{3}{x^{4}}\right)^{\prime}=\left(3x^{-4}\right)^{\prime}=-12x^{-5}
=-\dfrac{12}{x^5}$
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$\left(-\dfrac{3}{2x^{2}}\right)^{\prime}=\left(-\dfrac{3}{2}x^{-2}\right)^{\prime}=-\dfrac{3}{2}\times (-2)x^{-3}
=\dfrac{3}{x^3}$
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$\left(x^{\frac{1}{3}}\right)^{\prime}=\dfrac{1}{3}x^{\frac{1}{3}-1}
=\dfrac{1}{3}x^{-\frac{2}{3}}=\dfrac{1}{3\sqrt[3]{x^2}}$
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$\left(\sqrt[5]{x^2}\right)^{\prime}=
\left(x^{\frac{2}{5}}\right)^{\prime}=\dfrac{2}{5}x^{\frac{2}{5}-1}
=\dfrac{2}{5}x^{-\frac{3}{5}}=\dfrac{2}{5\sqrt[5]{x^3}}$
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$\left(2\sqrt[4]{x}\right)^{\prime}=
\left(2x^{\frac{1}{4}}\right)^{\prime}=2\times\dfrac{1}{4}x^{\frac{1}{4}-1}
=\dfrac{1}{2}x^{-\frac{3}{4}}=\dfrac{1}{2\sqrt[4]{x^3}}$
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$\left(\dfrac{3}{\sqrt[3]{x^2}}\right)^{\prime}=
\left(3x^{-\frac{2}{3}}\right)^{\prime}
=3\times \left(-\dfrac{2}{3}\right)x^{-\frac{2}{3}-1}
=-2x^{-\frac{5}{3}}=\dfrac{-2}{\sqrt[3]{x^5}}$
【問 5.17終わり】
解答例一覧へ