経済学で出る数学

ワークブックでじっくり攻める:応用問題


CES関数の正規化


【問】 CES関数, \[ f(x_1,x_2)=({\alpha}_1x_1^{\rho}+{\alpha}_2x_2^{\rho})^{\frac{1}{{\rho}}} \] は \[ f(x_1,x_2)=A({\rho})({\beta}x_1^{\rho}+(1-{\beta})x_2^{\rho})^{\frac{1}{{\rho}}} \] と書けることを示しなさい.

【解答】
\begin{align*} f(x_1,x_2)&=({\alpha}_1x_1^{\rho}+{\alpha}_2x_2^{\rho})^{\frac{1}{{\rho}}}\\ &=\Bigl[({\alpha}_1+{\alpha}_2)(\dfrac{{\alpha}_1}{{\alpha}_1+{\alpha}_2}x_1^{\rho}+\dfrac{{\alpha}_2}{{\alpha}_1+{\alpha}_2}x_2^{\rho})\bigr]^{\frac{1}{{\rho}}}\\ &=({\alpha}_1+{\alpha}_2)^{\frac{1}{{\rho}}}\Bigl[(\dfrac{{\alpha}_1}{{\alpha}_1+{\alpha}_2}x_1^{\rho}+ (1-\dfrac{{\alpha}_1}{{\alpha}_1+{\alpha}_2})x_2^{\rho})\bigr]^{\frac{1}{{\rho}}}\\ \end{align*} なので, $A({\rho})=({\alpha}_1+{\alpha}_2)^{\frac{1}{{\rho}}}$, ${\beta}=\dfrac{{\alpha}_1}{{\alpha}_1+{\alpha}_2}$とすればよい.
【解答終】

【Further Reading】
Hal R. Varian ‘Microeconomic Analysis; Third Edition,’ W.W.Norton & Company (1992)
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